I am just completely lost with this problem...thanks if you can help!
Find the exact area of the surface obtained by rotating the given curve about the x-axis.
x = 6t - 2t^3
y = 6t^2
0 ≤ t ≤ 1
I think you set up the integral of (dy/dt)/(dx/dt) but then I don't know where to go from there. Please help!! thanks a bunch!