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I am just completely lost with this problem...thanks if you can help!

Find the exact area of the surface obtained by rotating the given curve about the x-axis.

x = 6t - 2t^3

y = 6t^2

0 ≤ t ≤ 1

I think you set up the integral of (dy/dt)/(dx/dt) but then I don't know where to go from there. Please help!! thanks a bunch!

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